itoa
原型: char * itoa ( int value, char * str, int base );
value:要轉換的值
str:目的地字串空間,可以是一個矩陣
base:數值型態,16、10、2進制
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| /* itoa example */
#include <stdio.h>
#include <stdlib.h>
int main ()
{
int i;
char buffer [33];
printf ("Enter a number: ");
scanf ("%d",&i);
itoa (i,buffer,10);
printf ("decimal: %s\n",buffer);
itoa (i,buffer,16);
printf ("hexadecimal: %s\n",buffer);
itoa (i,buffer,2);
printf ("binary: %s\n",buffer);
return 0;
}
|
Output:
Enter a number: 1750
decimal: 1750
hexadecimal: 6d6
binary: 11011010110
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